Le forum de XCAS

Hello

why does the distributive law not hold for complex numbers?

simplify((3+4*i)*x+(4-3*i)*y) [enter] (3+4*i)*x+(4-3*i)*y

but

simplify((3+4*j)*x+(4-3*j)*y) [enter] 4*j*x - 3*j*y + 3*x+4*y

Some menu functions that are very useful
Currently, only SELECT is available.

Menu
Select all
Edit selection
simplify
normal
factor
approx
exact
eval
Back
Forward

I like this online version because it looks like the PC version. Suggestion, the [sel] button should perform the same [Menu] functions as the PC version. I have tested on tablets and the buttons are manageable, but on a mobile it is very difficult, I think for mobiles a version with bigger buttons i...

Hello but some CAS (MAXIMA) include it within the list of set instructions, it is important to have an alias to '*' as an explicit name, I think it costs nothing to extend the functionality of this command, as well as including the complement of a set command, and creating a submenu of set commands ...

Hello xCas has set operation commands, for a future version please add a submenu 'SET' in the PC version, however the following command is very important in set theory cartesian_product( set[1], set[a,b] ) [enter] => A X B= {(1,a),(1,b)} this is to expand the functionality of cartesian_product if th...

Hello, ox xCas PC The help field of the UNION command says that it is an infix command, but the example is shown as a prefix. likewise for minus and intersect union is an infixed operator to get the union of 2 sets. union((Vect or Set),(Vect or Set)) => union is an infixed operator to get the union ...

Hello, To obtain the complement of a set with respect to another set you can use the MINUS command, but it would be nice to create a separate command Please add this command as a function as it is a fundamental command in set theory A := set[2,3,5,7,11]; B := set[1,2,3,4,5,6,7,8,9,10,11]; C:= set[];...

hHello solve has the option to display the variable in the solution, so it would be nice to use fsolve as well. fsolve((((2*x-1) NTHROOT (3^(x^2-3)))) = (3*sqrt(3)),x,) [enter] [−0.436491673104,3.4364916731] fsolve((((2*x-1) NTHROOT (3^(x^2-3)))) = (3*sqrt(3)),x,'=') [enter] [x=−0.436491673104, x=3....

hello normal cmd ok I think these would be good examples to attach to the xCas documentation simplify(((1/3)*x+(23/9))*(3*x+1)+(88/9)) => (3*x^2+24*x+37) / 3 normal(((1/3)*x+(23/9))*(3*x+1)+(88/9)) => x^2 + 8*x + 37/3 as you can see the difference between the two commands. I think it would also be u...

Hello. I copied the examples wrong the parameter pol, would try to take the result to an expression without quotient, that is to say it would distribute in each term automatically simplify(((1/3)*x+(23/9))*(3*x+1)+(88/9)) [Enter] returns (3*x^2+24*x+37)/3 simplify(((1/3)*x+(23/9))*(3*x+1)+(88/9), 'p...

Hello, working with relations on sets. for example: R={ [x,y] ∈ R ⁄ ((y=x^2 ) ∧ (x ∈ Z) ∧ (-3≤x≤3 ) ) } f:=unapply(x^2,x); [enter] (x)->x^2 X_:=[-3,-2,-1,0,1,2,3]; [enter] [-3,-2,-1,0,1,2,3] // input set apply(f,X_); [enter] [9,4,1,0,1,4,9] apply((x)->x^2,[-3,-2,-1,0,1,2,3]); [enter] [9,4,1,0,1,4,9]...

The documentation showing the PC version of xcas for the base b logarithm of an argument is incomplete.

Logarithm with base b.
logb(Real)

=>

Logarithm with base b.
logb(Expr, Expr)

and in the log function, LOGB should be added.

When simplifying, the result is often expressed as a rational expression, a second parameter could be accepted to try to simplify as a polyonomy. simplify(((1/3)*x+(23/9))*(3*x+1)+(88/9)) [Enter] returns (3*x^2+24*x+37)/3 simplify(((1/3)*x+(23/9))*(3*x+1)+(88/9), 'pol') [Enter] returns x^2+9*x^1+20*...

Hello:

here is a link to the outputs when assuming m=0

https://mathsolver.microsoft.com/en/sol ... x%2Bb)%3E0

Trying to solve the following equation,. and assuming the slope as positive or negative works well, but assuming m=0 does not. assume(m>0); solve((m*x+b)>0,x); [Enter] x>-b/m assume(m<0); solve((m*x+b)>0,x); [Enter] x<-b/m assume(m=0); assume(b>0); solve((m*x+b)>0,x); [Enter] is expected x=x (0*x)>-...