evalb command

[compsystems]

Hello

Hello, the boolen evaluation command when it cannot return a logical value must return the same input expression.
autosimplify(0); [enter]
evalb( (6+8*i)=(3+4*i) ) [enter] true
evalb( (6+8*i)≠(3+4*i) ) [enter] true
evalb( (6+8*i)>(3+4*i) ) [enter] evalb( (6+8*i)>(3+4*i) ) // why is the order evalb() being placed again?
evalb( (6+8*i)>(3+4*i) ) [enter] (6+8*i)>(3+4*i) : )

autosimplify(2); [enter]
evalb( (6+8*i)>(3+4*i) ) [enter] evalb((3+4*i)>0)

[parisse]

I don't understand what you want, is it the suppression of evalb?

[compsystems]

Yes, I think you should remove the command in the output and leave just the argument

evalb( (6+8*i)>(3+4*i) ) [enter] (6+8*i)>(3+4*i)

message "no order in complex numbers"