Is there a step function?
Publié : jeu. août 31, 2017 12:25 am
In my class we have been doing Laplace transforms of arbitrary piecewise functions. For example:
f(t)=t-(t-2)*u(t-2)-u(t-4)
where u is a unit step function.
The Laplace transform of (t-1)*u(t-1) should be 1/s^2*exp(-2*s)
My question is, is there a u(t) step function in xcas that can be used in the laplace() function. Am I being clear in this? I know the ilaplace(1) is Dirac(). So, Dirac() is an impulse function?
Matt
f(t)=t-(t-2)*u(t-2)-u(t-4)
where u is a unit step function.
The Laplace transform of (t-1)*u(t-1) should be 1/s^2*exp(-2*s)
My question is, is there a u(t) step function in xcas that can be used in the laplace() function. Am I being clear in this? I know the ilaplace(1) is Dirac(). So, Dirac() is an impulse function?
Matt