find a relation (set) with XCAS
Publié : sam. sept. 28, 2019 4:22 pm
Hello BP
How do I solve the following problem with Xcas? I tried using the ASSUME () command but I can't get the answer
A := set[ 2, 4, 5, 6 ]; B := set[ 1, 2, 3, 5 ]
R = { ( b, a ) ∈ BxA / a <= 6 - 2*b }
R -> set[ ( 1, 2 ), ( 1, 4 ), ( 2, 2 ) ] // answer
How do I solve the following problem with Xcas? I tried using the ASSUME () command but I can't get the answer
A := set[ 2, 4, 5, 6 ]; B := set[ 1, 2, 3, 5 ]
R = { ( b, a ) ∈ BxA / a <= 6 - 2*b }
R -> set[ ( 1, 2 ), ( 1, 4 ), ( 2, 2 ) ] // answer