Hello
It is important to show the complete factorization of a number, so is there a possibility of obtaining the product of factors without powers?
ifactor(18) [enter] 2^1*3^2
ifactor(18, '*') [enter] '2*3*3'
ifactor(#) => #1 * #2 * ... * #n
Modérateur : xcasadmin
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Re: ifactor(#) => #1 * #2 * ... * #n
Will be available with ifactors(n,'*')
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- Messages : 568
- Inscription : sam. févr. 04, 2017 11:34 pm
- Localisation : Colombia
- Contact :
Re: ifactor(#) => #1 * #2 * ... * #n
Tested on version 1.99.0 - 990 and it works excellently
ifactors(18,'*') [Enter] Returns 2*3*3
ifactors(18,'*') [Enter] Returns 2*3*3