Hello,
I am using xcas 1.1.4-16 (c) 2000-14.
I found the following equation would not simplify:
eq1: = 1.2 * H * phi = (2 * H * nH2O)
eq2: nH2O = = solve (eq1, nH2O) [0]
eq3: = simplify (eq2)
eq4: = simplify (eq3)
eq5: = expand (eq4)
I get nH2O = (0.6 * H * phi / H) as a result. The H / H will not cancel. Any suggestions?
Thank you
simplification error
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simplification error
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Re: simplification error
hello
with "xcas 1.2.0 (c)"
eq1:= 1.2 * H * phi = (2 * H * nH2O)
eq2:= solve (eq1, nH2O) [0]
eq3:=factor(eq2)
or
eq1:= 12/10 * H * phi = (2 * H * nH2O)
eq2:= solve (eq1, nH2O) [0]
eq3:=simplify(eq2)
I suppose there is differents algorithms with real or rationals numbers.
with "xcas 1.2.0 (c)"
eq1:= 1.2 * H * phi = (2 * H * nH2O)
eq2:= solve (eq1, nH2O) [0]
eq3:=factor(eq2)
or
eq1:= 12/10 * H * phi = (2 * H * nH2O)
eq2:= solve (eq1, nH2O) [0]
eq3:=simplify(eq2)
I suppose there is differents algorithms with real or rationals numbers.